Delete the whole argument group, parentheses and all. Jump onto the first ( with f(, then delete to its match with d%.
result = compute(a, b, (c + d), e) + trailing
Canonical solution: f( d% · par: 4 keystrokes (vimgolf rules — every keypress counts).
% jumps between matching (), [], {} — and as a motion, d% deletes the entire balanced pair and everything inside, even when they're nested. No counting brackets by eye.
Reading about keystrokes doesn't build keystrokes. Try this in a real vim buffer right now — the “Balanced demolition” mission takes about a minute.
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