Balanced demolition — vim

Try it on a real buffer

Delete the whole argument group, parentheses and all. Jump onto the first ( with f(, then delete to its match with d%.

result = compute(a, b, (c + d), e) + trailing

Canonical solution: f( d% · target: 4 keystrokes — the fewest that solve it (every keypress counts).

Why it works

% jumps between matching (), [], {} — and as a motion, d% deletes the entire balanced pair and everything inside, even when they're nested. No counting brackets by eye.

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